Simple calculator using Python

Simple Artihmetic calculator using python using if-else statement



num1=int(input('Enter Number 1 \t: '))
num2=int(input('Enter Number 2 \t: '))
print('1. Addition')
print('2. Subtraction')
print('3. Multiplication')
print('4. Division')

choice=input('Enter a choice, Press Q to quit : ')

if(choice)=='1':
    sum=num1+num2   
    print('The Sum is \t\t= \t', sum)
elif(choice)=='2':
    diff=num1-num2
    print('The Difference is \t= \t', diff)
elif(choice)=='3':
    mul=num1*num2
    print('The Product is \t\t= \t', mul)
elif(choice)=='4':
    div=num1/num2
    print('The Division is \t= \t', div)
elif(choice=='q' or choice=='Q'):
    print('Exiting...')
else:
    print('Enter a valid choice')